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/*
single linked list merge
This problem requires you to merge two ordered singly linked lists into one ordered singly linked list
*/
// I AM NOT DONE
use std::fmt::{self, Display, Formatter};
use std::ptr::NonNull;
use std::vec::*;
#[derive(Debug)]
struct Node<T> {
val: T,
next: Option<NonNull<Node<T>>>,
}
impl<T> Node<T> {
fn new(t: T) -> Node<T> {
Node {
val: t,
next: None,
}
}
}
#[derive(Debug)]
struct LinkedList<T> {
length: u32,
start: Option<NonNull<Node<T>>>,
end: Option<NonNull<Node<T>>>,
}
impl<T> Default for LinkedList<T> {
fn default() -> Self {
Self::new()
}
}
impl<T> LinkedList<T> {
pub fn new() -> Self {
Self {
length: 0,
start: None,
end: None,
}
}
pub fn add(&mut self, obj: T) {
let mut node = Box::new(Node::new(obj));
node.next = None;
let node_ptr = Some(unsafe { NonNull::new_unchecked(Box::into_raw(node)) });
match self.end {
None => self.start = node_ptr,
Some(end_ptr) => unsafe { (*end_ptr.as_ptr()).next = node_ptr },
}
self.end = node_ptr;
self.length += 1;
}
pub fn get(&mut self, index: i32) -> Option<&T> {
self.get_ith_node(self.start, index)
}
fn get_ith_node(&mut self, node: Option<NonNull<Node<T>>>, index: i32) -> Option<&T> {
match node {
None => None,
Some(next_ptr) => match index {
0 => Some(unsafe { &(*next_ptr.as_ptr()).val }),
_ => self.get_ith_node(unsafe { (*next_ptr.as_ptr()).next }, index - 1),
},
}
}
pub fn merge(list_a:LinkedList<T>,list_b:LinkedList<T>) -> Self
{
//TODO
Self {
length: 0,
start: None,
end: None,
}
}
}
impl<T> Display for LinkedList<T>
where
T: Display,
{
fn fmt(&self, f: &mut Formatter) -> fmt::Result {
match self.start {
Some(node) => write!(f, "{}", unsafe { node.as_ref() }),
None => Ok(()),
}
}
}
impl<T> Display for Node<T>
where
T: Display,
{
fn fmt(&self, f: &mut Formatter) -> fmt::Result {
match self.next {
Some(node) => write!(f, "{}, {}", self.val, unsafe { node.as_ref() }),
None => write!(f, "{}", self.val),
}
}
}
#[cfg(test)]
mod tests {
use super::LinkedList;
#[test]
fn create_numeric_list() {
let mut list = LinkedList::<i32>::new();
list.add(1);
list.add(2);
list.add(3);
println!("Linked List is {}", list);
assert_eq!(3, list.length);
}
#[test]
fn create_string_list() {
let mut list_str = LinkedList::<String>::new();
list_str.add("A".to_string());
list_str.add("B".to_string());
list_str.add("C".to_string());
println!("Linked List is {}", list_str);
assert_eq!(3, list_str.length);
}
#[test]
fn test_merge_linked_list_1() {
let mut list_a = LinkedList::<i32>::new();
let mut list_b = LinkedList::<i32>::new();
let vec_a = vec![1,3,5,7];
let vec_b = vec![2,4,6,8];
let target_vec = vec![1,2,3,4,5,6,7,8];
for i in 0..vec_a.len(){
list_a.add(vec_a[i]);
}
for i in 0..vec_b.len(){
list_b.add(vec_b[i]);
}
println!("list a {} list b {}", list_a,list_b);
let mut list_c = LinkedList::<i32>::merge(list_a,list_b);
println!("merged List is {}", list_c);
for i in 0..target_vec.len(){
assert_eq!(target_vec[i],*list_c.get(i as i32).unwrap());
}
}
#[test]
fn test_merge_linked_list_2() {
let mut list_a = LinkedList::<i32>::new();
let mut list_b = LinkedList::<i32>::new();
let vec_a = vec![11,33,44,88,89,90,100];
let vec_b = vec![1,22,30,45];
let target_vec = vec![1,11,22,30,33,44,45,88,89,90,100];
for i in 0..vec_a.len(){
list_a.add(vec_a[i]);
}
for i in 0..vec_b.len(){
list_b.add(vec_b[i]);
}
println!("list a {} list b {}", list_a,list_b);
let mut list_c = LinkedList::<i32>::merge(list_a,list_b);
println!("merged List is {}", list_c);
for i in 0..target_vec.len(){
assert_eq!(target_vec[i],*list_c.get(i as i32).unwrap());
}
}
}